64、请编制函数READDAT（）实现从文件IN.DAT中读取1000个十进制整数到数组XX中;再
#define MAX 1000
int xx[MAX],odd=0,even=0;
double aver=0.0,totfc=0.0;
void WriteDat(void) ;
int ReadDat(void)
{
FILE *fp ;
if((fp=fopen("in.dat","r"))==NULL) return 1;
fclose(fp) ;
return 0 ;
}
void Compute(void)
{
}
void main()
{
int i ;
for(i=0;i<MAX;i++)
xx[i]=0;
if(ReadDat())
{printf("Can't open the data file in.dat!\007\n") ;
return;
}
Compute();
printf("ODD=%d\nEVEN=%d\nAVER=%lf\nTOTFC=%lf\n", odd,even,aver,t
otfc);
WriteDat();
}
void WriteDat(void)
{
FILE *fp;
int i;
fp=fopen("out.dat", "w") ;
fprintf(fp, "%d\n%d\n%lf\n%lf\n",odd,even,aver,totfc);
fclose(fp) ;
}
/* 注：*/
int ReadDat(void)
{
FILE *fp ;
int i;
if((fp=fopen("in.dat","r"))==NULL) return 1;
for(i=0;i<MAX;i++)
{fscanf(fp,"%d,",&xx[i]);
if(feof(fp)) break;
}
fclose(fp) ;
return 0 ;
}
void Compute(void)
{
int i,yy[1000];
for(i=0;i<MAX;i++)
{aver+=xx[i];
if(xx[i]%2)
odd++;
else
even++;
}
aver/=(odd+even);
for(i=0;i<MAX;i++)
totfc+=(xx[i]-aver)*(xx[i]-aver)/(odd+even);
}